Find the sum of the following APs:
0.6, 1.7, 2.8, . . ., to 100 terms.
Here a = 0.6
d = 1.7 – 0.6 = 1.1 And, n = 100 We know that,
= 50 x [2 x 0.6 + (100 - 1) x 1.1]
= 50 x [1.2 + 108.9]
= 50 x 110.1 = 5505.0
Hence, the sum of first 100 terms of the given
A.P. = 5505.
Write first four terms of the AP, when the first term a and the common difference d are given as follows:
a = – 1.25, d = – 0.25
For the following APs, write the first term and the common difference
3, 1, – 1, – 3, . . .
For the following APs, write the first term and the common difference
– 5, – 1, 3, 7, . . .
For the following APs, write the first term and the common difference
0.6, 1.7, 2.8, 3.9, . . .
Which of the following are APs ? If they form an AP, find the common difference d and write three more terms.
– 1.2, – 3.2, – 5.2, – 7.2, . . .
Which of the following are APs ? If they form an AP, find the common difference d and write three more terms.
–10, –6, –2, 2, ....
Mock Test Series
