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Triangles

Question
CBSEENMA10007382

Triangle ABC is right-angled at B and D is the mid-point of BC. Prove that AC2 = 4AD2 - 3AB2.


Solution
In right ∆ABC, by Pythagoras Theorem.
AC2 = BC2 + AB2...(i)
Similarly, in rt. ∆ABD,
AD2 = BD2 + AB2
                 
space equals open parentheses 1 half BC close parentheses squared plus AB squared space space space space space space space space space space space space space space space space left square bracket because space BD space equals space 1 half BC right square bracket
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rightwards double arrow                            4 AD squared space equals space BC squared plus 4 AB squared
rightwards double arrow                             BC squared space equals space 4 AD squared minus 4 AB squared         ...(ii)
From (i) and (ii), we  get
                         AC squared equals 4 AD squared minus 4 AB squared plus AB squared
space Hence comma space space space AC squared equals 4 AD squared minus 3 AB squared space space space space Proved