Question
In the given figure. DE || AC and DF || AE. Prove that
Solution
Given DE || AC and DF || AE
To prove:![<pre>uncaught exception: <b>mkdir(): Permission denied (errno: 2) in /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/util/sys/Store.class.php at line #56mkdir(): Permission denied</b><br /><br />in file: /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/util/sys/Store.class.php line 56<br />#0 [internal function]: _hx_error_handler(2, 'mkdir(): Permis...', '/home/config_ad...', 56, Array)
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#6 {main}</pre>](/application/zrc/images/qvar/MAEN10042113-2.png)
Proof : In ∆ABE, we have
DF || AE
Therefore, by using Basic proportionality theorem, we have
In ∆ABC, we have
DE || AC
Therefore, by using Basic proportionality theorem, we have
Comparing (i) and (ii), we get
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#6 {main}</pre>](/application/zrc/images/qvar/MAEN10042113-5.png)
Hence proved.
To prove:
Proof : In ∆ABE, we have
DF || AE
Therefore, by using Basic proportionality theorem, we have
In ∆ABC, we have
DE || AC
Therefore, by using Basic proportionality theorem, we have
Comparing (i) and (ii), we get
Hence proved.
