A wire is in the shape of a rectangle. Its length is 40 cm and breadth is 22 cm. If the same wire is rebent in the shape of a square, what will be the measure of each side. Also find which shape encloses more area?

Solution

Perimeter of rectangle = Perimeter of square

2 (Length + Breadth) = 4 × Side

2 (40 + 22) = 4 × Side

2 × 62 = 4 × Side

Side = $\frac{124}{4}$ = 31 cm

Area of rectangle = 40 × 22 = 880 cm²

Area of square = (Side)² = 31 × 31 = 961 cm²

Therefore, the square-shaped wire encloses more area.

Some More Questions From Perimeter and Area Chapter

For Daily Free Study Material Join wiredfaculty