Question

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Complete the last column of the table.

S. No.

Equation

Value

Say, whether the equation is satisfied. (Yes/No)

(i)

x + 3 = 0

x = 3

–

(ii)

x + 3 = 0

x = 0

–

(iii)

x + 3 = 0

x = − 3

–

(iv)

x − 7 = 1

x = 7

–

(v)

x − 7 = 1

x = 8

–

(vi)

5x = 25

x = 0

–

(vii)

5x = 25

x = 5

–

(viii)

5x = 25

x = − 5

–

(ix)

$\frac{m}{3} = 2$

m = − 6

–

(x)

$\frac{m}{3} = 2$

m = 0

–

(xi)

$\frac{m}{3} = 2$

m = 6

–

Solution

(i) x + 3 = 0

L.H.S. = x + 3

By putting x = 3,

L.H.S. = 3 + 3 = 6 ≠ R.H.S.

∴ No, the equation is not satisfied.

(ii) x + 3 = 0

L.H.S. = x + 3

By putting x = 0,

L.H.S. = 0 + 3 = 3 ≠ R.H.S.

∴ No, the equation is not satisfied.

(iii) x + 3 = 0

L.H.S. = x + 3

By putting x = −3,

L.H.S. = − 3 + 3 = 0 = R.H.S.

∴ Yes, the equation is satisfied.

(iv) x − 7 = 1

L.H.S. = x − 7

By putting x = 7,

L.H.S. = 7 − 7 = 0 ≠ R.H.S.

∴ No, the equation is not satisfied.

(v) x − 7 = 1

L.H.S. = x − 7

By putting x = 8,

L.H.S. = 8 − 7 = 1 = R.H.S.

∴ Yes, the equation is satisfied.

(vi) 5x = 25

L.H.S. = 5x

By putting x = 0,

L.H.S. = 5 × 0 = 0 ≠ R.H.S.

∴ No, the equation is not satisfied.

(vii) 5x = 25

L.H.S. = 5x

By putting x = 5,

L.H.S. = 5 × 5 = 25 = R.H.S.

∴ Yes, the equation is satisfied.

(viii) 5x = 25

L.H.S. = 5x

By putting x = −5,

L.H.S. = 5 × (−5) = −25 ≠ R.H.S.

∴ No, the equation is not satisfied.

(ix) $\frac{m}{3}$ = 2

L.H.S. = $\frac{m}{3}$

By putting m = −6,

L. H. S. = $\frac{- 6}{3} = - 2$ ≠ R.H.S.

∴No, the equation is not satisfied.

(x) $\frac{m}{3}$ = 2

L.H.S. = $\frac{m}{3}$

By putting m = 0,

L.H.S. = $\frac{0}{3} = 0$ ≠ R.H.S.

∴No, the equation is not satisfied.

(xi) $\frac{m}{3}$ = 2

L.H.S. = $\frac{m}{3}$

By putting m = 6,

L.H.S. = $\frac{6}{3} = 2$ = R.H.S.

∴ Yes, the equation is satisfied.

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S. No.	Equation	Value	Say, whether the equation is satisfied. (Yes/No)
(i)	x + 3 = 0	x = 3	–
(ii)	x + 3 = 0	x = 0	–
(iii)	x + 3 = 0	x = − 3	–
(iv)	x − 7 = 1	x = 7	–
(v)	x − 7 = 1	x = 8	–
(vi)	5x = 25	x = 0	–
(vii)	5x = 25	x = 5	–
(viii)	5x = 25	x = − 5	–
(ix)	$\frac{m}{3} = 2$	m = − 6	–
(x)	$\frac{m}{3} = 2$	m = 0	–
(xi)	$\frac{m}{3} = 2$	m = 6	–