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Probability

Question
CBSEENMA9003534

A well with 10 m inside diameter is long 14 m deep. Earth taken out of it is spread all around it to a width of 5 m to form an embankment. Find the height of the embankment.

Solution
Radius of the wall
(r) = 10 over 2 straight m equals 5 space straight m

Depth of the wall (h) = 10 m Volume of the earth dug out = Volume of the well = π r2h = π(5)2(10) = 250π m3 Radius of the well with embankment (R)
= 5 + 5 = 10 m π Area of the embankment
= Area of the well with embankment
– Area of the well without embankment = πR2 – πr2 = π(R + r) (R – r)
= π(10 + 5) (10 – 5)
= 75π m2
∴ Height of the embankment
equals fraction numerator Volume space of space the space earth space dug space out over denominator Area space of space the space embankment end fraction
 equals fraction numerator 250 straight pi over denominator 75 straight pi end fraction
equals 10 over 3 space straight m