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Probability

Question
CBSEENMA9003522

A lead pencil consists of a cylinder of wood with a solid cylinder of graphite filled in the interior. The diameter of the pencil is 7 mm and the diameter of the graphite is 1 mm. If the length of the pencil is 14 cm, find the volume of the wood and that of the graphite.

Solution

For solid cylinder of graphite
Diameter = 1 mm
therefore   Radius (r) = 1 half space mm

Length of the pencil (h) = 14 cm = 140 mm

∴ Volume of the graphite = straight pir2h
equals 22 over 7 cross times open parentheses 1 half close parentheses squared cross times 140 equals 110 space mm cubed
equals fraction numerator 110 over denominator 10 cross times 10 cross times 10 end fraction space cm cubed equals 0.11 space cm cubed
For cylinder of wood
Diameter = 7 mm
therefore space space  Radius (R) = 7 over 2  mm
Length of the pencil (h) = 14 cm = 140 mm
therefore  Volume of the wood 
equals straight pi left parenthesis straight R squared minus straight r squared right parenthesis straight h equals 22 over 7 open curly brackets open parentheses 7 over 2 close parentheses squared minus open parentheses 1 half close parentheses squared close curly brackets space 140
equals space 5280 space mm cubed equals fraction numerator 5280 over denominator 10 cross times 10 cross times 10 end fraction space cm cubed equals 5.28 space cm cubed