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Probability

Question
CBSEENMA9003411

The diameter of roller 1.5 m long is 84 cm. If it takes 100 revolutions to level a playground, find the cost of levelling this ground at the rate of 50 paise per square metre.

Solution
For roller

straight r equals fraction numerator 1.5 over denominator 2 end fraction space straight m space equals space 0.75 space straight m
 h = 84  cm = 0.84 m
therefore  Curved surface area = 2 πrh
       equals 2 cross times 22 over 7 cross times 0.75 cross times 0.84
equals space 3.96 space straight m squared

∴ Area of the ground levelled in 1 revolution = 3.96 m2
∴ Area of the ground levelled in 100 revolutions
= 3.96 x 100 m2 = 396 m2
∴ Cost of levelling

equals straight र space 396 space cross times 50 over 100
equals space र space 198