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Probability

Question
CBSEENMA9003721

A hemispherical bowl is made of steel 0.25 cm thick. The inner radius of the bowl is 5 cm. Find the outer curved surface area of the bowl.

Solution

Thickness of bowl = 0.25 cm Inner radius of bowl = 5 cm
∴ Outer radius of bowl
= 5 cm + 0.25 cm = 5.25 cm
∴ Outer curved surface area of the bowl = 2πr2
equals 2 cross times 22 over 7 cross times 5.25 space cm squared
= 33 cm2