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Statistics

Question
CBSEENMA9003289

A triangle and a parallelogram have the same base and the same area. If the sides of the triangle are 15 cm, 14 cm and 13 cm and the parallelogram stands on the base 15 cm, find the height of the parallelogram.

Solution

For triangle
a = 15 cm b = 14 cm c = 13 cm
therefore space space space space space space space space space space space space straight s equals fraction numerator straight a plus straight b plus straight c over denominator 2 end fraction equals fraction numerator 15 plus 14 plus 13 over denominator 2 end fraction equals 21 space cm
therefore space space space Area space equals space square root of straight s left parenthesis straight s minus straight a right parenthesis left parenthesis straight s minus straight b right parenthesis left parenthesis straight s minus straight c right parenthesis end root
space space space space space space space space space space space space space equals space square root of 21 left parenthesis 21 minus 15 right parenthesis left parenthesis 21 minus 14 right parenthesis left parenthesis 21 minus 13 end root
space space space space space space space space space space space space space equals square root of 21 left parenthesis 6 right parenthesis left parenthesis 7 right parenthesis left parenthesis 8 right parenthesis end root
space space space space space space space space space space space space space equals space 84 space cm squared

Let the height of the parallelogram be h cm. Then, area of the parallelogram
= Base x Height = 15 x h = 15h cm2 According to the question,
Area of the parallelogram
                   = Area of the triangle
rightwards double arrow space space space space 15 straight h space equals space 84
rightwards double arrow space space space space space space straight h space equals 84 over 15 equals 5.6 space cm

Hence, the height of the parallelogram is 5.6 cm.



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