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Statistics

Question
CBSEENMA9003284

A floral design on a floor is made up of 16 tiles which are triangular, the sides of the triangle being 9 cm, 28 cm and 35 cm. Find the cost of polishing the tiles at the rate of 50 p per cm2.


Solution

For one tile
a = 9 cm b = 28 cm c = 35 cm
therefore space space space space space space space space straight s equals fraction numerator straight a plus straight b plus straight c over denominator 2 end fraction
space space space space space space space space space space space space equals space fraction numerator 9 plus 28 plus 35 over denominator 2 end fraction equals 36 space cm
 
therefore   Area of one tile
 equals square root of straight s left parenthesis straight s minus straight a right parenthesis left parenthesis straight s minus straight b right parenthesis left parenthesis straight s minus straight c right parenthesis end root
equals square root of 36 left parenthesis 36 minus 9 right parenthesis left parenthesis 36 minus 28 right parenthesis left parenthesis 36 minus 35 right parenthesis end root
equals space square root of 36 left parenthesis 27 right parenthesis left parenthesis 8 right parenthesis left parenthesis 1 right parenthesis end root
equals square root of 36 left parenthesis 9 cross times 3 right parenthesis left parenthesis 4 cross times 2 right parenthesis end root
equals space 6 cross times 3 cross times 2 square root of 6 equals 36 square root of 6 space c m squared
therefore  Area of 16 tiles
        equals 36 square root of 6 cross times 16 equals 576 square root of 6 space cm squared
∴ Cost of polishing the tiles at the rate of 50 p per cm2.
equals space 576 square root of 6 cross times 50 space straight p space equals space straight र fraction numerator 576 square root of 6 cross times 50 over denominator 100 end fraction
equals straight र space 288 square root of 6 equals straight र space 705.60

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