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Statistics

Question
CBSEENMA9003247

Sides of a triangle are in the ratio of 12 :17 : 25 and its perimeter is 540 cm. Find its area.

Solution

Let the sides of the triangle be 12k, 17k and 25 k cm.
Then,
Perimeter = 12k+ 17k + 25k = 54k
According to the question,
54k = 540
rightwards double arrow space space space space space straight k equals 540 over 54
rightwards double arrow   k = 10
therefore   a = 12k = 12 x 10 = 120 cm
       b = 17k = 17 x 10 = 170 cm
       c = 25k = 25 x 10 = 250 cm
therefore space space space space straight s space equals space fraction numerator straight a plus straight b plus straight c over denominator 2 end fraction equals fraction numerator 120 plus 170 plus 250 over denominator 2 end fraction
space space space space space space space space space equals space 540 over 2 equals 270 space cm
therefore space space space Area space space equals space square root of straight s left parenthesis straight s minus straight a right parenthesis left parenthesis straight s minus straight b right parenthesis left parenthesis straight s minus straight c right parenthesis end root
space space space space space equals space square root of 270 left parenthesis 270 minus 120 right parenthesis left parenthesis 270 minus 120 right parenthesis left parenthesis straight v minus 250 right parenthesis end root
space space space space space equals square root of 270 left parenthesis 150 right parenthesis left parenthesis 100 right parenthesis left parenthesis 20 right parenthesis end root
space space space space space equals square root of left parenthesis 9 cross times 30 right parenthesis left parenthesis 5 cross times 30 right parenthesis left parenthesis 5 cross times 20 right parenthesis left parenthesis 20 right parenthesis end root
space space space space space equals space left parenthesis 3 right parenthesis left parenthesis 30 right parenthesis left parenthesis 5 right parenthesis left parenthesis 20 right parenthesis space cm squared space equals space 9000 space cm squared.

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