The triangular side walls of a flyover have been used for advertisements. The sides of the walls are 122 m, 22 m and 120 m (see figure). The advertisements yield an earning of र5000 per m² per year. A company hired one of its walls for 3 months. How much rent did it pay?

Solution

a =122 m
b = 22 m
c = 120 m
$therefore space space space space straight s equals fraction numerator straight a plus straight b plus straight c over denominator 2 end fraction equals fraction numerator 122 plus 22 plus 120 over denominator 2 end fraction straight m space space space space space space space space equals space 264 over 2 space space straight m space equals space 132 space straight m$

1 year =12 months
V Rent for 12 months per m²= र 5000

$therefore space$ Rent for 1 month per m² = र $5000 over 2$
$therefore$ Rent for 3 months of 1320 m²
$equals space र 5000 over 12 cross times 3 equals space र space 1250$

$therefore space space$ Rent for 3 months of 1320 m²
= र (1250 x 1320)
= र 1650000.

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The triangular side walls of a flyover have been used for advertisements. The sides of the walls are 122 m, 22 m and 120 m (see figure). The advertisements yield an earning of र5000 per m² per year. A company hired one of its walls for 3 months. How much rent did it pay?

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Statistics

The triangular side walls of a flyover have been used for advertisements. The sides of the walls are 122 m, 22 m and 120 m (see figure). The advertisements yield an earning of र5000 per m2 per year. A company hired one of its walls for 3 months. How much rent did it pay?

Some More Questions From Statistics Chapter

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

The triangular side walls of a flyover have been used for advertisements. The sides of the walls are 122 m, 22 m and 120 m (see figure). The advertisements yield an earning of र5000 per m² per year. A company hired one of its walls for 3 months. How much rent did it pay?