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Surface Areas And Volumes

Question
CBSEENMA9003181

Construct the following angles and verify by measuring them by a protractor:

135°

Solution

135°

Given: A ray OA.
Required: To construct an angle of 135° at O. Steps of Construction:
1. Produce AO to A' to form ray OA'.
2. Taking O as centre and some radius, draw an arc of a circle, which intersects OA at a point B and OA' at a point B'.
WiredFaculty

3. Taking B as centre and with the same radius as before, draw an arc intersecting the previously drawn arc at a point C.
4. Taking C as centre and with the same radius as before, draw an arc intersecting the arc drawn in step 1, say at D.
5. Draw the ray OE passing through C.
Then ∠EOA = 60°.
6. Draw the ray OF passing through D.
Then ∠FOE = 60°.
7. Next, taking C and D as centres and with the radius more than 1 halfCD, draw arcs to intersect each other, say at G.
8. Draw the ray OG intersecting the arc drawn in step 1 at H. This ray OG is the bisector of the angle FOE, 
WiredFaculty

9. Next, taking B' and H as centres and with the radius more than the radius more than  1 halfB'H, draw arcs to intersect each other, say at I.

10. Draw the ray OI. This ray 01 is the bisector of the angle B'OG, i.e., ∠B'OI = ∠GOI
WiredFaculty

On measuring the ∠IOA by protractor, we find that ∠IOA = 135°.
Thus, the construction is verified.