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Surface Areas And Volumes

Question
CBSEENMA9003179

Construct the following angles and verify by measuring them by a protractor:

75°

Solution

(i) 75°

Given: A ray OA.
Required: To construct an angle of 75° at O.
Steps of Construction:
1. Taking O as centre and some radius, draw an arc of a circle, which intersects OA, say at a point B.

2. Taking B as centre and with the same radius as before, draw an arc intersecting the previously drawn arc, say at a point C.
3. Taking C as centre and with the same radius as before, draw an arc intersecting the arc drawn in step 1, say at D.
4. Join the ray OE passing through C. Then ∠EOA = 60°.
5. Draw the ray OF passing through D. Then ∠FOE = 60°.
6. Next, taking C and D as centres and with the radius more than 1 half CD, draw arcs to intersect each other, say at G.
7. Draw the ray OG intersecting the arc of step 1 at H. This ray OG is the bisector of the intersect each other, say at G. 7. Draw the ray OG intersecting the arc of step 1 at H. This ray OG is the bisector of the angle FOE, 
straight i. straight e. comma space space angle FOG equals angle EOG equals 1 half
angle FOE equals 1 half left parenthesis 60 degree right parenthesis equals 30 degree
8. Next, taking C and H as centres and with the radius more than 1 half CH, draw arcs to intersect each other, say at I.
9. Draw the ray OI. This ray OI is the bisector of the angle GOE, 
straight i. straight e. comma space space space space angle GOI equals angle EOI equals 1 half
angle GOE equals 1 half left parenthesis 30 degree right parenthesis equals 15 degree
Thus comma space angle IOA equals angle IOE plus angle EOA equals 15 degree plus 60 degree
On measuring the ∠IOA by protractor, we find that ∠IOA = 15°.
Thus the construction is verified.