The area of an isosceles triangle whose base is ‘a’ and equal sides are of length ‘b’ is
$straight a over 4 square root of 4 straight b squared minus straight a squared end root$
$straight b over 4 square root of 4 straight b squared minus straight a squared end root$
$straight b over 2 square root of 4 straight b squared minus straight a squared end root$
$straight a over 2 square root of 4 straight b squared minus straight a squared end root$

Solution

straight a over 4 square root of 4 straight b squared minus straight a squared end root

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