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Constructions

Question

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In figure, if AD is a median of ΔABC, then

ar(ΔABD) = ar(ΔADC)
ar(ΔABD) > ar(ΔADC)
ar(ΔABD) < ar(ΔADC)
ar(ΔABD) = 1/3 ar(ΔABC)

Solution

A.

ar(ΔABD) = ar(ΔADC)

Some More Questions From Constructions Chapter

Prove that of all parallelograms of which the sides are given, the parallelogram which is a rectangle, has the greatest area.

In the figure, diagonals AC and BD of a trapezium ABCD with AB || CD intersect each other at O. Show that ar(Δ AOD) = ar(Δ BOC).

Parallelograms on the same base and between same parallels are equal in area. Prove this.

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