Question
In the given figure, ΔABC is right angled at A and AD is its median. BA is produced to E such that BA = AE. ED is joined. If AB = 6 cm, BC = 10 cm, find ar(ΔBED).

Solution
In right triangle BAC,
AB2 + AC2 = BC2
| By Pythagoras Theorem
⇒ 62 + AC2 = 102 ⇒ AC = 8 cm
∵ AD is a median of ΔABC ∴ ar(ΔABD) = ar(ΔACD)
∵ A median of a triangle divides it into two triangles of equal areas
∵ BA = AE ∴ A is the mid-point of BE ∴ DA is a median of ΔBDE
∵ A median of a triangle divides it into two triangles of equal areas