Question
In the given figure, ΔABC is right angled at B, and BD is its median. E is the mid-point of BD. If AB = 6 cm, AC = 10 cm, calculate area of ΔBEC.

Solution
In right triangle ABC,
AB2 + BC2 = AC2
| By Pythagoras theorem ⇒ 62 + BC2 = 102
⇒ BC = 8 cm
∵ BD is a median of ΔABC
∵ A median of a triangle divides it into two triangles of equal areas ⇒ ar(ΔBCD) = 12 cm2 ...(2)
∵ E is the mid-point of BD ∴ CE is a median of ΔBCD
∵ A median of a triangle divides it into two triangles of equal areas