+91-8076753736 [email protected]

-->

Constructions

Question

Wired Faculty App

ABCD is a parallelogram in which BC is produced to E such that CE = BC (see figure). AE intersects CD at F. Prove that ar(ΔBFC) $equals 1 fourth space ar left parenthesis ABCD right parenthesis.$

Solution

Solution not provided.

Some More Questions From Constructions Chapter

Prove that of all parallelograms of which the sides are given, the parallelogram which is a rectangle, has the greatest area.

In the figure, diagonals AC and BD of a trapezium ABCD with AB || CD intersect each other at O. Show that ar(Δ AOD) = ar(Δ BOC).

Parallelograms on the same base and between same parallels are equal in area. Prove this.

ABCD is a quadrilateral and BD is one of its diagonals as shown in figure. Show that ABCD is a parallelogram and find its area.

In the given figure, AB | | DC. Show that ar(BDE) = ar(ACED).

In the given figure, ABED is a parallelogram in which DE = EC. Show that area (ABF) = area (BEC)

Mock Test Series

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation