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Areas Of Parallelograms And Triangles

Question
CBSEENMA9002581

In an isosceles triangle ABC, with AB = AC, the bisectors of ∠B and ∠C intersect each other at O. Join A to O. Show that:

(i) OB = OC
(ii) AO bisects ∠A.

Solution

Given: In an isosceles triangle ABC, with AB = AC, the bisectors of ∠B and ∠C intersect each other at O. Join A to O.
To Prove: (i) OB = OC
(ii) AO bisects ∠A.
Proof: (i) AB = AC    | Given
∴ ∠B = ∠C
| Angles opposite to equal sides of a triangle are equal

therefore space 1 half angle straight B equals 1 half angle straight C
∴ ∠OBC = ∠OCB
| ∵ BO and CO are the bisectors of ∠B and ∠C respectively
∴ OB = OC
| Sides opposite to equal angles of a triangle are equal
(ii) In ∆OAB and ∆OAC,
AB = AC    | Given
OB = OC | Proved in (i) above
OA = OA    | Common
∴ ∠B = ∠C
| Angles opposite to equal sides of a triangle are equal
therefore space space space 1 half angle straight B equals 1 half angle straight C

∴ ∠ABO = ∠ACO
| ∵ BO and CO are the bisectors of ∠B and ∠C respectively
∴ ∆OAB ≅ ∆OAC | By SAS Rule
∴ ∠OAB = ∠OAC    | C.P.C.T.
∴ AO bisects ∠A.