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Circles

Question
CBSEENMA9002762

ABCD is a quadrilateral in which P, Q, R and S are mid-points of the sides AB, BC, CD and DA (see figure). AC is a diagonal. Show that:



left parenthesis straight I right parenthesis space space SR parallel to space AC space and space SR space equals 1 half space AC
(ii)    PQ = SR
(iii)    PQRS is a parallelogram.

Solution
Given: ABCD is a quadrilateral in which P, Q, R and S are mid-points of the sides AB, BC, CD and DA. AC is a diagonal.
To Prove:  left parenthesis straight I right parenthesis space space SR parallel to space AC space and space SR space equals 1 half space AC
                (ii)    PQ = SR
                (iii)    PQRS is a parallelogram.
Proof : (i) In increment DAC
because S is the mid-pouint of DA and R is the mid-point of DC
therefore SR parallel to AC and SR= 1 half AC
                                      | MId-point therorem
(ii) In increment B AC
because P is the mid-pouint of AB and Q is the mid-point of BC
therefore space space space PQ space parallel to space AC space space and space PQ equals 1 half AC
                                          | Mid-point theorem
But from (i) SR equals 1 half AC
therefore  PQ = SR


(iii) PQ || AC    | From (ii)
SR || AC    | From (i)
∴ PQ || SR
| Two lines parallel to the same line are parallel to each other
Also, PQ = SR    | From (ii)
∴ PQRS is a parallelogram.
| A quadrilateral is a parallelogram if a pair of opposite sides are parallel and are of equal length

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Some More Questions From Circles Chapter

Show that if the diagonals of a quadrilateral bisect each other at right angles, then it is a rhombus.

 Show that the diagonals of a square are equal and bisect each other at right angles.

Show that if the diagonals of a quadrilateral are equal and bisect each other at right angles, then it is a square.

Diagonal AC of a parallelogram ABCD bisects ∠A (see figure). Show that:
(i)    it bisects ∠C also
(ii)    ABCD is a rhombus.

ABCD is a rhombus. Show that diagonal AC bisects ∠A as well as ∠C and diagonal BD bisects ∠B as well as ∠D.

ABCD is a rectangle in which diagonal AC bisects ∠A as well as ∠C. Show that (i) ABCD is a square (ii) diagonal BD bisects ∠B as well as ∠D.

In parallelogram ABCD, two points P and Q are taken on diagonal BD such that DP = BQ (see figure). Show that:


(i)    ∆APD ≅ ∆CQB
(ii)   AP = CQ
(iii)  ∆AQB ≅ ∆CPD
(iv)  AQ = CP
(v)   APCQ is a parallelogram.

ABCD is a parallelogram and AP and CQ are perpendiculars from vertices A and C on diagonal BD respectively (see figure). Show that:
(i) ∆APB ≅ ∆CQD
(ii) AP = CQ.

In ∆ABC and ∆DEF, AB = DE, AB || DE, BC = EF and BC || EF. Vertices A, Band C are joined to vertices D, E and F respectively (see figure). Show that:
(i)     quadrilateral ABED is a parallelogram
(ii)    quadrilateral BEFC is a parallelogram
(iii)   AD || CF and AD = CF
(iv)   quadrilateral ACFD is a parallelogram



(v)     AC = DF
(vi)    ∆ABC ≅ ∆DEF. [CBSE 2012

ABCD is a trapezium in which AB || CD and AD = BC (see figure): Show that
(i)      ∠A = ∠B
(ii)    ∠C = ∠D
(iii)    ∆ABC = ∆BAD
(iv)    diagonal AC = diagonal BD.



[Hint. Extend AB and draw a line through C parallel to DA intersecting AB produced at E.]