Check which of the following are solutions of the equation x – 2y = 4 and which are not:
$open parentheses square root of 2 comma space 4 square root of 2 close parentheses$

Solution

open parentheses 2 comma space 4 square root of 2 close parentheses

Put x =

square root of 2

, y =

4 square root of 2

in(1), we get
x - 2y =

square root of 2 minus 2 left parenthesis 4 square root of 2 right parenthesis

equals space square root of 2 minus 8 square root of 2 equals negative 7 square root of 2

which is not 4.

therefore space space left parenthesis square root of 2 comma space 4 square root of 2 right parenthesis

is not a solution of (1).

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