In figure, ∆ABC is an equilateral triangle with co-ordinates of B and C as B (1, 0) and C (5, 0). Find the co-ordiantes of vertex A.
Let D be the middle point of BC. Join AD. Then, ∠BDA = 90°
∵ ∆ABC is an equilateral triangle
∴AB = AC = BC
⇒ AB = BC
⇒ AB = 5 - 1 = 4 = BC BD = 3 - 1 = 2
In right triangle BDA,
AB2 = AD2 + BD2 (4)2 = AD2 + (2)2
16 = AD2 + 4
AD2 = 12
AD =