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Coordinate Geometry

Question
CBSEENMA9001874

Verify that x3 + y3 + z3 - 3xyz = 1 half (x + y + z)[(x - y)2 + (y - z)2 + (z - x)2].

Solution

L.H.S.  = x+ y3 + z3 -3xyz
= (x + y + x) (x2 + y+ z2 -xy - yz -zx) 
                                | Using Identity VIII
equals 1 half (x+y+z){2x2 + 2y2 + z2 -xy -yz -zx)
equals 1 half (x+y+z){2x2 + 2y2 + 2z2 -2xy -2yz -2zx)
equals 1 half (x + y + z) {x2 - 2xy + y2 ) (y-2yz + z2) + (z- 2zx + x2 )}
equals 1 half left parenthesis straight x plus straight y plus straight z right parenthesis left curly bracket left parenthesis straight x minus straight y right parenthesis squared plus left parenthesis straight y space minus space straight z right parenthesis squared plus space left parenthesis straight z space minus straight x right parenthesis squared right square bracket
                                          | Using Identity II