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Polynomials

Question

The simplified form of $13 to the power of begin display style 1 fifth end style end exponent over 13 to the power of begin display style 1 third end style end exponent$ is :
$13 to the power of 2 over 15 end exponent$
$13 to the power of 8 over 15 end exponent$
$13 to the power of 1 third end exponent$
$13 to the power of negative 2 over 15 end exponent$

Solution

13 to the power of negative 2 over 15 end exponent