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Coordinate Geometry

Question
CBSEENMA9001776
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Find the value of k, if x - 1 is a factor of p(x) in each of the following cases:

p(x) = kx2 - square root of 2 to the power of straight x end root plus 1

Solution

p(x) = kx2 - square root of 2 x plus 1
If x - 1 is a factor of p(x), then p(1) = 0
                                          | By Factor Theorem
  rightwards double arrow          k(1)2 - square root of 2 to the power of open parentheses space 1 space close parentheses end exponent end root + 1 = 0
  rightwards double arrow space space space space space space space space space space space space straight k minus square root of 2 plus 1 equals 0 rightwards double arrow space space space space space space space space space space space space space straight k space equals space square root of 2 minus 1

Some More Questions From Coordinate Geometry Chapter

Which of the following expressions are polynomials in one variable and which are not? State reasons for your answer.

4x2 - 3x + 7

Which of the following expressions are polynomials in one variable and which are not? State reasons for your answer.

x10+ y3 + t50

Write the coefficients of x2 in each of the following:

2 + x2 + x

Write the coefficients of x2 in each of the following:
2 - x2 + x3

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