Question
Find p(0), p(1) and p(2) for each of the following polynomials:
p(t) = 2 + t + 2t2 - t3
Solution
p(t) = 2 + t + 2t2 - t3
∴ p(0) = 2 + 0 + 2(0)2 - (0)3 = 2,
p(1) = 2 + 1 + 2(1)2 - (1)3
= 2 + 1 + 2 - 1 = 4,
and, p(2) = 2 + 2 + 2(2)2 - (2)3
= 2 + 2 + 8 - 8 = 4.
