Question
Find p(0), p(1) and p(2) for each of the following polynomials:
p(y) = y2 - y + 1
Solution
p(y) = y2 - y + 1
∴ p(0) = (0)2 - (0) + 1 = 1,
p(1) = (1)2 - (1) + 1 = 1,
and, p(2) = (2)2 - (2) + 1 = 4 - 2 + 1 = 3.
