Question
A bag contains 5 red balls, 8 white balls, 4 green balls and 7 black balls. If one ball is drawn at random, find the probability that it is
(i) black
(ii) not green.
Solution
In the bag,
number of red balls = 5
number of white balls = 8
number of green balls = 4
number of black balls = 7
∴ Total number of balls in the bag = 5 + 8 + 4 + 7 = 24
(i) Number of black balls = 7
∴ Probability that the ball drawn is black
(ii) Number of balls that are not green
= 5 + 8 + 7 = 20
∴ Probability that the ball drawn is not green