The edge of a cube is 2 cm. Find the total surface area of the cuboid formed by three such cubes joined edge to edge.

The edge (side) of the given cube = 2 cm
Since, there such cubes are joined, then
Total length (l) = (2+2+2) cm
                         = 6 cm
Breadth (b) = 2 cm
Height (h) = 2 cm

∴   Total surface area of the resultant cuboid
                                                  = 2[lb + bh + hl]
                                                  = 2[6 x 2 + 2 x 2 + 2 x 6] cm²
                                                  = 2[28] cm²
                                                  = 56 cm²
Thus, the required total surface area of the cuboid = 56 cm².