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Question
CBSEENMA8003361

The shape of a garden is rectangular in the middle and semi-circular at the ends as shown in the diagram. Find the area and the perimeter of this garden. [Length of rectangle is 20 - (3.5 + 3.5) meters.]

Solution
For the semi-circular part:
Diameter of the semi-circle = 7 m
∴  Radius of the semi-circle = 7 over 2 equals 3.5 space straight m
     Area of the 2 semi-circles =space space space space 2 open square brackets 1 half πr squared close square brackets
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                                               equals 22 over 7 cross times 35 over 10 cross times 35 over 10 space straight m squared
                                               equals space fraction numerator 11 cross times 35 over denominator 10 end fraction straight m squared space equals space 38.5 space straight m squared
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                                                         equals space 2 cross times 22 over 7 cross times 35 over 10 space straight m
                                                          = 22 m
For rectangular part:
                            Length of the rectangle = 20 - (3.5 + 3.5) m
                                                                 = 13 m
                            Breadth of the rectangle = 7 m
∴                                                     Area = Length x Breadth
                                                                = 13 m x 7 m
                                                                = 91 m2
                                      Perimeter = 2 x [Length + Breadth]
                                                      = 2 x [13 m + 0 m]
                                        = 2 x  13 m
                                        = 26 m
Now, Area of the garden = (38.5 + 91)m2
                                        = 129.5 m2
Perimeter of the garden = 22 m + 26 m
                                      = 48 m