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Factorisation

Question
CBSEENMA8002817
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Factorise the following expression:

10a2 - 15b2 + 20c2


Solution

∵                   10a2 = 2 × 5 × a × a = (5) [2 × a × a]
                     15b2 = 3 × 5 × b × b = (5) [3 × b × b]
                     20c2 = 2 × 2 × 5 × c × c = (5)[2 × 2 × c × c]
∴  10a2 - 15b2 + 20c2 = (5)[2 × a × a + 3b × b + 2 × 2 × c × c]
                             = 5[2a2+  3b2 + 4c2]
 



 
 

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