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Playing With Numbers

Question
CBSEENMA8002726

Check what the result would have been if sundaram had chosen the numbers shown below. 1. 27 2. 39 3. 64 4. 17

Solution

1.                      Chosen number = 27
         Number with reversed digits = 72
            Sum of the two numbers  = 27 + 72 = 99
Now,                                   99  = 11[9]
                                              = 11[2 + 7]
                                              = 11(Sum of the digits of the chosen number)

2.                         Chosen number = 39
            Number with reversed digits = 93
                Sum of the two numbers = 39 + 93 = 132
Now,                              132 + 11 = 12
i,e,                                 132 = 11[12]
                                           = 11 [ 3 + 9]
                                           = 11 [ Sum of the digits of the chosen number]            

3.                                     Chosen number = 64
                       Number with reversed digits  = 46
                                                    Sum   = 64 + 46 = 110
Now,                                                110 = 11[10]
                                                            = 11[6 + 4]
                                                 = 11[ Sum of the digits of the chosen number  
4.                                      Chosen number    =  17
                        Number with reversed digits     = 71
                                                        Sum   =  17 + 71 = 88
Now,                                                    88    = 11[8]
                                                                 = 11[1+7]
                                                   = 11[Sum of the digits of the chosen number]