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Linear Equations In One Variable

Question
CBSEENMA8002288

Half of a herd of deer are grazing in the field and three-fourths of the remaining are playing nearby. The rest 9 are drinking water from the pond. Find the number of deer in the herd.

Solution

Let the number of deer = x

∴ Number of deer:     Grazing in the field = x over 2
                            Playing nearly = 3 over 4 cross times(Remaining no of deer)
                                               = 3 over 4 cross times open parentheses x minus x over 2 close parentheses
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#6 {main}</pre> 
                                               = fraction numerator 3 x over denominator 8 end fraction
                                 Drinking water = 9

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#6 {main}</pre>
  Transposing 9 to RHS, and x to LHS, we have
                              x over 2 plus fraction numerator 3 x over denominator 8 end fraction minus x equals negative 9
or                            fraction numerator 4 x plus 3 x minus 8 x over denominator 8 end fraction equals negative 9
or                                     fraction numerator negative straight x over denominator 8 end fraction equals negative 9
   Multiply by 8 on both sides we have
  
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#6 {main}</pre>
or                               -x = -72
or                               x = 72
     Thus, the number of deer in herd = 72

Some More Questions From Linear Equations in One Variable Chapter

Solve the following equation:

2x -3 = 7