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Linear Equations In One Variable

Question
CBSEENMA8002280
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One of the two digits of a two digit number is three times the other digit. If you interchange the digits of this two-digit number and add the resulting number to the original number, you get 88. What is the original number?

Solution

             Let the digit at unit place = x

∴                 The digit at tens place = 3x
                         The number = 10(3x) + x
                                         = 30x + x
                                         = 31x
   On interchanging the digits, the number = 10x + 3x
                                                       =13x
   According to the condition, we have
                                             31x + 13x = 88
or                                                    44x = 88
    Dividing both sides by 44, we have
                                      fraction numerator 44 x over denominator 44 end fraction equals 88 over 44
or                                        x = 2

∴                               The number = 31 cross times 2
                                                 = 62


                                             


Some More Questions From Linear Equations in One Variable Chapter

Solve the following equation:

x-2=7

Solve the following equation:

y + 3 = 10

Solve the following equation:

6 = z + 2

Solve the following equations:

x - 2 = 7

Solve the following equation:

6 = z + 2

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