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Linear Equations In One Variable

Question
CBSEENMA8002182

Three consecutive integers add up to 51. What are these integers?

Solution

Let consecutive numbers be, x, x+1 and x+2.
According to the condition, we have
          x + [x+1] +[x+2] =51
or                x + x + 1 + x + 2 =51
or                              3x + 3 = 51
   Transposing 3 to RHS, we have
                                3x = 51 - 3 = 48
  Dividing both sides by 3, we have:
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#6 {main}</pre>   or  x =16
Now                         x + 1 = 16 + 1 = 17
and                          x + 2 = 16 + 2 =18   
    Thus, the required three consecutive numbers are: 16, 17 and 18.