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Molecular Basis Of Inheritance

Question
CBSEENBI12003327

In a 3.2 Kbp long piece of DNA, 820 adenine bases were found. What would be the number of cytosine bases?

  • 780

  • 1560

  • 740

  • 1480

Solution

A.

780

Total DNA = 3.2 Kbp = 3200 bp

Adenine = 820

According to Chargaff's rule

[A] = [T]; [G] = [C]

So, Thymine = 820

Therefore, total A + T content = 820 + 820 = 1640

Also, A + T = 3200 - (G + C)

So, G + C content = 3200 - 1640 = 1560

So, Cytosine = 15602 = 780