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Principles Of Inheritance And Variation

Question
CBSEENBI12003076

A woman with two genes (one on each X-chromosome) for haemophilia and one gene for colour blindness on the X-chromosome marries a normal man. How will the progeny be?

  • All sons and daughters are haemophilic and colourblind

  • Haemophilic and colourblind daughters

  • 50% haemophilic colourblind sons and 50% haemophilic sons

  • 50% haemophilic daughters and 50% colourblind daughters

Solution

C.

50% haemophilic colourblind sons and 50% haemophilic sons

Haemophilia and colour blindness both are recessive X-linked traits. They express in males when present in single copy (heterozygous) but in females, they express only when present in homozygous condition.