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Principles Of Inheritance And Variation

Question
CBSEENBI12046881
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Percentage of recombination between A and B is 9%, A and C is 17%, B and C is 26% , then the arrangement of genes is

  • ABC

  • ACB

  • BCA

  • BAC

Solution

D.

BAC

One map unit or centimorgan is equivalent to 1% recombination between two genes. The frequency of recombination can be used to depict the arrangement of the genes. 

Recombination frequency between three genes is:

(i) A - B = 9%

(ii) A - C = 17%

(iii) B - C = 26%

By manipulating all the three possibilities of their arrangements A - B -C, A -C - B and B - A - C, it was found that the three gene must be arranged in the order B - A - C with distance B - A = 9 cM and A - C = 17 cM and the distance being 26 cM.

Some More Questions From Principles of Inheritance and Variation Chapter

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