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Principles Of Inheritance And Variation

Question
CBSEENBI12047594

The linkage map of X-chromosome of fruit-fly has 66 units, with yellow body gene (y) at one end and bobbed hair (b) gene at the other end. The recombination frequency between these two genes (y and b) should be

  • 50%

  • 100%

  • 66%

  • > 50%

Solution

B.

100%

The actual distance between two genes is said to be equivalent to the percentage of crossing over between these rwo genes. Since the two genes lie at the ends of the chromosome, there are 100 per cent chance of their segregation during crossing over.