In a plant species, flower colour yellow is dominant over white and fruit shape round is dominant over elongated. Crossing was performed between two pure lines - one having yellow-flower and round-fruit and another with white-flower and elongated-fruit. About 20 plants survived in F₁ progeny. Plants of F₁ were allowed to self-fertilise and about 960 plants survived in F₂. If the traits follow Mendelian inheritance, the number of plants would have yellow-flower and round-fruit in F₁ and F₂ are respectively

20, 960

20, 540

10, 180

10, 60

Solution

20, 540

Ratio of the species is as followes:-

Yellow Rounded : Yellow Elongated : White Rounded : White Elongated

4 : 3 : 3 : 1

Now, out of total 960 species survived in F₂ generation. The number of plants that would have yellow flower and round fruit in F₂ generation will be

$\frac{9 (round yellow)}{16 (total progeny)} \times 960$

(Total survived) = 540 plants.

Thus, in F₁ and F₂ -generation, total yellow colour, round fruit plants survived will be are 20, 540.

Some More Questions From Principles of Inheritance and Variation Chapter

For Daily Free Study Material Join wiredfaculty