Question
The volume of water to be added to 100 cm3 of 0.5 NH2SO4 to get decinormal concentration is
100 cm3
450 cm3
500 cm3
400 cm3
Solution
D.
400 cm3
N1V1 = N2V2
Given, N1 = 0.5 N, N2 = 0.1 N
V1 = 100 cm3 (Total final volume)
Therefore, Volume to be added
= 500- 100 = 400 cm3
