A first-order reaction has a specific reaction rate of 10^–2 s^–1. How much time will it take for 20 g of the reactant to reduce to 5 g?

238.6 second

138.6 second

346.5 second

693.0 second

Solution

138.6 second

straight t subscript 1 divided by 2 end subscript space equals space fraction numerator 0.693 over denominator 10 to the power of negative 2 end exponent end fraction

For the reduction of 20 g of reactant to 5 g, two t_1/2 is required.

therefore space straight t space equals space 2 space straight x space fraction numerator 0.693 over denominator 10 to the power of negative 2 end exponent end fraction space second space equals space 138.6 space second

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