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Electrochemistry

Question
CBSEENCH12011491

The value of reaction quotient [Q], for the following cell

Zn(s)|Zn2+ (0.01 M)|| Ag+ (1.25 M | Ag (s) is

  • 156

  • 125

  • 1.25 x 10-2

  • 6.4 x 10-3

Solution

D.

6.4 x 10-3

The cell reaction is

Zn(s) → Zn2+ (0.01 M) + 2e-

[Ag+ (1.25 M) + e- → Ag (s)] x 2

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Zn(s) + 2Ag+ (1.25 M) → Zn2+ (0.01 M) + 2Ag(s)

 Q = [Zn2+][Ag+]2 = 0.01(1.25)2 = 6.4 x 10-3

value of Q = 6.4 x 10-3