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The Solid State

Question
CBSEENCH12011337
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Percentage of free space in a body centred cubic unit cell is 

  • 30%

  • 32%

  • 34%

  • 28%

Solution

B.

32%

Packing fraction

space equals space fraction numerator Volume space occupied space by space atoms space in space straight a space unit space cell over denominator Volume space of space the space unit space cell end fraction For space body space centred space cube comma space Packing space fraction space equals space fraction numerator 2 space straight x begin display style 4 over 3 end style πr cubed over denominator open parentheses begin display style fraction numerator 4 straight r over denominator square root of 3 end fraction end style close parentheses squared end fraction space equals space fraction numerator square root of 3 space straight pi over denominator 8 end fraction space equals space 0.68 where comma space edge space length space straight a space equals space fraction numerator 4 straight r over denominator square root of 3 end fraction therefore comma space volume space space ccupiedf space equals space 68 and space volume space vacant space space equals space 32 percent sign

Some More Questions From The Solid State Chapter

Ionic solids conduct electricity in liquid state but not in solid state. Explain.

What type of solids are electrical conductors, malleable and ductile?

Give the significance of a 'lattice point'.

Name the parameters that characterize a unit cell.

Distinguish between Hexagonal and monoclinic unit cells.

Distinguish between Face-centred and end-centred unit cells.

What is the two-dimensional coordination number of a molecule in square close packed layer ?

A compound is formed by two elements M and N. The element N forms ccp and atoms of M occupy 1/3 of tetrahedral voids. What is the formula of the compound?

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