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The Solid State

Question
CBSEENCH12011329
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Volume occipied by one molecule of water (density = 1 g cm-3) is

  • 9.0 x 10-23

  • 6.023 x 10-23 cm3

  • 3.0 x 10-23 cm3

  • 5.5 x 10-23 cm3

Solution

C.

3.0 x 10-23 cm3

6.02 x 1023 molecules of water = 1 mol
                                                  = 18 g
Therefore, Mass of one molecule of water
  fraction numerator 18 over denominator 6.023 space straight x space 10 to the power of 23 space straight g end fraction straight d equals space straight m over straight V therefore comma space straight V space equals space straight m over straight d space equals space fraction numerator 18 over denominator 6.023 space straight x space 10 to the power of 23 space straight x 1 end fraction space equals space 3 space straight x space 10 to the power of negative 23 space end exponent space cm cubed

Some More Questions From The Solid State Chapter

Give the significance of a 'lattice point'.

Name the parameters that characterize a unit cell.

Distinguish between Hexagonal and monoclinic unit cells.

Distinguish between Face-centred and end-centred unit cells.

What is the two-dimensional coordination number of a molecule in square close packed layer ?

A compound is formed by two elements M and N. The element N forms ccp and atoms of M occupy 1/3 of tetrahedral voids. What is the formula of the compound?

Which of the following lattices has the highest packing efficiency:

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