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Electrochemistry

Question
CBSEENCH12011301

Al2O3 is reduced by electrolysis at low potentials and high currents. If 4.5 x 104 An of current is passed through molten Al2O3 for 6h, what mass of aluminium is produced? (Assume 100% current efficiency, at.mass of Al = 27 g mol-1)

  • 9.0 x 103 g

  • 8.1 x 104 g

  • 2.4 x 105

  • 1.3 x 104 g

Solution

B.

8.1 x 104 g

Al2O3 ionises as, 
Al subscript 2 straight O subscript 3 space leftwards harpoon over rightwards harpoon space Al to the power of plus subscript cathode space plus space stack AlO subscript 3 superscript 3 minus end superscript with Anode below
At space Cathode
Al to the power of 3 plus end exponent space plus space stack 3 straight e to the power of minus with 3 straight F below space rightwards arrow stack space Al with 27 below

because space Mass space of space aluminium space deposited space by space 3 space straight F space of space
electricity space equals space 27
4.0 space straight x space 10 to the power of 4 space straight x space 6 space straight x space 3600 space straight C space of space electricy

space equals space fraction numerator 27 space straight x space 4.0 space straight x space 10 to the power of 4 straight x space 6 space straight x space 3600 over denominator 3 straight F end fraction
space equals space fraction numerator 27 space straight x space 4.0 space straight x space 10 to the power of 4 space straight x space 6 space straight x space 3600 over denominator 3 space straight x space 96500 end fraction straight g
space equals space 8.1 space straight x space 10 to the power of 4 space straight g