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The Solid State

Question
CBSEENCH12011368

The fraction of totoal volume occupied by the atoms present in a simple cube is: 

  • π/6

  • fraction numerator straight pi over denominator 3 square root of 2 end fraction
  • fraction numerator straight pi over denominator 4 square root of 2 end fraction
  • π /4

Solution

A.

π/6

For simple cubic
space Radius space left parenthesis straight r right parenthesis space equals space straight a over 2
Volume space of space the space atom space space equals space 4 over 3 straight pi open parentheses straight a over 2 close parentheses cubed
Packing space fraction space equals space open parentheses fraction numerator 4 over 3 straight pi open parentheses straight a over 2 close parentheses cubed over denominator straight a cubed end fraction close parentheses space equals space straight pi over 6