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Chemical Kinetics

Question
CBSEENCH12011230
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The half -life of a substance in a certain enzyme catalysed reaction is 138 s. The time required for the concentration of the substance to fall from 1.28 mg L-1 is 

  • 414 s

  • 552 s 

  • 690 s

  • 276 s

Solution

C.

690 s

Enzyme -catalysed reactions follow first order kinectics.
therefore,
Fall of concentration from 1.28 mg L-1 to 0.04 mg L-1 involves five half - lives.

1.28 space rightwards arrow with straight t subscript 1 divided by 2 end subscript on top space 0.64 space rightwards arrow with straight t subscript 1 divided by 2 end subscript on top space 0.32 space space 0.16 space rightwards arrow with straight t subscript 1 divided by 2 end subscript on top space 0.08 rightwards arrow with straight t subscript 1 divided by 2 end subscript on top space space 0.04 therefore comma Time space required space space equals space 5 space straight x space straight t subscript 1 divided by 2 end subscript space space equals space 5 space straight x space 138 space straight s space equals space 690 space straight s

Some More Questions From Chemical Kinetics Chapter

The conversion of molecules X to Y follows second order kinetics. If concentration of X is increased to three times how will it affect the rate of formation of Y?

What will be the effect of temperature on rate constant?

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